Establishing values[]
4e+17 kg/m³ as the density of neutronium as found by Executor (Density 1)
4e17kg/m³ ---> 4e+11kg/cm³
1,212,541,000t/cm³ as found by 19hmun (Density 2)
1,212,541,000t/cm³ ---> 1.1e+12kg/cm³
The other calc attempted to get the volume as an ellipsoid, but I think solving this as a paraboloid is a more efficient option.
Paraboloid (volume)= 1/2⋅π⋅b2⋅a
Where a = axis length b = cross length
Only assumption made: Kevin is 6ft tall.
The Feats[]
The Calcs[]
Paraboloid volume = 1/2⋅π⋅b2⋅a
Using 160.4m for A and 91.67m for B
We get 2117281.99m³ for the total volume.
Using the same formula, the volume for empty space is 1820333.91m³.
The empty space accounts for 85.98% of the volume.
2117281.99m³ - 85.98% = 2.96e5m³ or 2.96e11cm³.
Calculating the mass[]
Density 1[]
M = D * V
M = 4e+11kg/cm³ * 2.96e11cm³
M = 1.184e23kg
Based off the picture that depicted him lifting it off the ground and assuming he's still lifting it in the full-screen view, we get 18.693 degrees as the angle he's lifting it compared to the surface of the ground.
Mass * sin(18.693) should give us what he's truly lifting.
1.184e23kg * sin(18.693)
Mass = 3.7e22kg
Density 2[]
M = D * V
M = 1.1e+12kg/cm³ * 2.96e11cm³
M = 3.2e23kg
3.2e23kg * sin(18.693)
Mass = 1.026e23kg
Conclusion[]
- Density 1 = 3.7e22kg Class Z
- Density 2 = 1.026e23kg Class Z